(X^2)=(7x+44)

Solution for (X^2)=(7x+44) equation:

(X^2)=(7X+44)

We move all terms to the left:

(X^2)-((7X+44))=0


We calculate terms in parentheses: -((7X+44)), so:

(7X+44)

We get rid of parentheses

7X+44

Back to the equation:

-(7X+44)


We get rid of parentheses

X^2-7X-44=0

a = 1; b = -7; c = -44;
Δ = b2-4ac
Δ = -72-4·1·(-44)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-15}{2*1}=\frac{-8}{2}
=-4
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+15}{2*1}=\frac{22}{2}
=11
$